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Question: When a foreign object lodged in the


When a foreign object lodged in the trachea (windpipe) forces a person to cough, the diaphragm thrusts upward causing an increase in pressure in the lungs. This is accompanied by a contraction of the trachea, making a narrower channel for the expelled air to flow through. For a given amount of air to escape in a fixed time, it must move faster through the narrower channel than the wider one. The greater the velocity of the airstream, the greater the force on the foreign object. X rays show that the radius of the circular tracheal tube contracts to about two-thirds of its normal radius during a cough. According to a mathematical model of coughing, the velocity v of the airstream is related to the radius r of the trachea by the equation
V(r) = k(r0 – r)r2 1 2 r0 ≤ r ≤ r0
where k is a constant and r0 is the normal radius of the trachea.
The restriction on r is due to the fact that the tracheal wall stiffens under pressure and a contraction greater than 1/2 r0 is prevented (otherwise the person would suffocate).
(a) Determine the value of r in the interval [1/2 r0, r0] at
which v has an absolute maximum. How does this compare with experimental evidence?
(b) What is the absolute maximum value of v on the interval?
(c) Sketch the graph of v on the interval f0, r0 g.


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> Use mathematical induction (page 72) to show that if f (x) = xex, then f(n)(x) = (x + n)ex. Mathematical Induction In proving statements that involve a positive integer n, it is frequently helpful to use the following principle. Principle of Mathem

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> Calculate y’. y = cot (3x2 + 5)

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> Calculate y’. y = (1 – x-1)-1

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