Questions from General Calculus


Q: Let f(x) = √1-x2, o

Let f(x) = √1-x2, o < x < 1 (a). Find f-1. How is it related to f? (b). Identify the graph of f and explain your answer to part (a).

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Q: Graph several members of the family of functions f (x)

Graph several members of the family of functions f (x) = 1 /1 + aebx where a > 0. How does the graph change when changes? How does it change when a change?

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Q: Use Formula 10 to graph the given functions on a common screen

Use Formula 10 to graph the given functions on a common screen. How are these graphs related? y = log1.5 x, y = ln x, y = log10 x, y = log50 x

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Q: Use Formula 10 to graph the given functions on a common screen

Use Formula 10 to graph the given functions on a common screen. How are these graphs related? y = ln x, y = log10 x, y = ex, y = 10x

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Q: Graph the given functions on a common screen. How are these

Graph the given functions on a common screen. How are these graphs related?

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Q: Compare the functions f (x) = x0.1 and

Compare the functions f (x) = x0.1 and g (x) = in x by graphing both f and g in several viewing rectangles. When does the graph of f finally surpass the graph of g?

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Q: Starting with the graph of y = ex, find the equation

Starting with the graph of y = ex, find the equation of the graph that results from (a) reflecting about the line y = 4 (b) reflecting about the line x = 2

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Q: Suppose that f has domain A and g has domain B.

Suppose that f has domain A and g has domain B. (a). What is the domain of f + g? (b). What is the domain of fg? (c). What is the domain of f/g?

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Q: Graph the function f (x) = √x3 + x2

Graph the function f (x) = √x3 + x2 + x + 1 and explain why it is one-to-one. Then use a computer algebra system to find an explicit expression for f-1(x). (Your CAS will produce three possible expres...

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Q: (a). If g (x) = x6 + x4

(a). If g (x) = x6 + x4, x > 0 use a computer algebra system to find an expression for g-1 (x). (b). Use the expression in part (a) to graph y = g (x), y = x, and y = g-1 (x) on the same screen.

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