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Question: Two liters of liquid A are mixed


Two liters of liquid A are mixed with two liters of liquid B. The resulting volume is only 3.95 L. Explain what happened on the molecular level.



> Provide an explanation for the fact that most decomposition reactions are endothermic but most combination reactions are exothermic.

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> a. Write the equilibrium constant expression for the reaction: C(s) + H2O(g)↽−−−−⇀CO(g) + H2 (g) b. Calculate the equilibrium constant if [H2O] = 0.40 M [CO] = 0.40 M [H2] = 0.20 M

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> label solution as isotonic, hypotonic, or hypertonic in comparison to 0.9% (m/V) NaCl (0.15 M NaCl). 3% (m/V) NaCl

> label solution as isotonic, hypotonic, or hypertonic in comparison to 0.9% (m/V) NaCl (0.15 M NaCl). 0.35 M glucose

> A gas mixture has three components, N2, F2, and He. The partial pressure of N2 is 0.35 atm and F2 is 0.45 atm. If the total pressure is 1.20 atm, what is the partial pressure of helium?

> Determine the osmolarity of 2.5 × 10-4 M C6H12O6 (nonelectrolyte).

> Two solutions, A and B, are separated by a semipermeable membrane. For each case, predict whether there will be a net flow of water in one direction and, if so, which direction. A is 0.10 M NaCl and B is 0.20 M glucose.

> Two solutions, A and B, are separated by a semipermeable membrane. For each case, predict whether there will be a net flow of water in one direction and, if so, which direction. A is 0.10 M glucose and B is 0.10 M KCl.

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> A sample of O2 gas occupies 257 mL at 208C and 1.20 atm. What is the volume of this O2 gas sample at STP?

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> A 300.0-mL portion of H2O is added to 300.0 mL of 0.250 M H2SO4. What is the new molarity?

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> Calculate the molarity of 2.75 L of solution containing 1.35 × 10-2 mol HCl.

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> Calculate the composition of each of the following solutions in mass/mass %: a. 1.00 g KCl in 1.00 × 102 g solution b. 50.0 g KCl in 5.00 × 102 mL solution (d = 1.14 g/mL)

> Calculate the composition of each of the following solutions in mass/volume %: a. 20.0 g benzene dissolved in 1.00 × 102 mL solution b. 20.0 g acetic acid dissolved in 2.50 L solution

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> Explain the large difference in boiling point (b.p.) for the isomer’s butanol and diethyl ether. нн нн нн ||| | Н-с—с- с —с—о — н нн Н-с—с- о —с—с — Н H H нн нн H H diethyl ether b.p. %3D 34.5°С butanol b.p. = 117°C

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> Why does water’s abnormally high boiling point help to make it a desirable solvent?

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> Express each of the following in units of atm: a. 128 cm Hg b. 255 torr c. 1405 mm Hg d. 303 kPa

> Describe the molecular/atomic basis of gas pressure.

> What is the trend for atom size from top to bottom down a group?

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2.99

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